3x^3-4x^2-5x+2=0.
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解:方程化为一般式后，用因式分解法化为：x^3-4x^2+5x-2=0f(x) =x^3-4x^2+5x-2f(1) = 0x^3-4x^2+5x-2 =(x-1)(x^2+ax+2)coef. of x2-a=5a=-3x^3-4x^2+5x-2=0(x-1)(x^2-3x+2)=0(x-1)(x-1)(x-2)=0x=1 or 2
咨询记录 · 回答于2022-10-26
3x^3-4x^2-5x+2=0.
亲
，很高兴为您解答，3x^3-4x^2-5x+2=0.：x³-x²-(3x²-5x+2)=0x²(x-1)-(3x-2)(x-1)=0(x-1)(x²-3x+2)=0(x-1)²(x-2)=0x=1,x=2
，很高兴为您解答，3x^3-4x^2-5x+2=0.：x³-x²-(3x²-5x+2)=0x²(x-1)-(3x-2)(x-1)=0(x-1)(x²-3x+2)=0(x-1)²(x-2)=0x=1,x=2
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演变的过程再详细点
解:方程化为一般式后，用因式分解法化为：x^3-4x^2+5x-2=0f(x) =x^3-4x^2+5x-2f(1) = 0x^3-4x^2+5x-2 =(x-1)(x^2+ax+2)coef. of x2-a=5a=-3x^3-4x^2+5x-2=0(x-1)(x^2-3x+2)=0(x-1)(x-1)(x-2)=0x=1 or 2
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