简便计算(1+1/2+1/3+1/4)×(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4+1/5)×(1/2+1/3+1/4)
1个回答
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设a=(1/2+1/3+1/4),b=(1/2+1/3+1/4+1/5)
原式=(1+a)*b-(1+b)*a
=b+ab-a-ab
=b-a
=1/5
原式=(1+a)*b-(1+b)*a
=b+ab-a-ab
=b-a
=1/5
追问
要小学的,中学的太深奥
追答
(1+1/2+1/3+1/4)x(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4+1/5)x(1/2+1/3+1/4)
=(1+1/2+1/3+1/4)x(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4)x(1/2+1/3+1/4)-1/5 x(1/2+1/3+1/4)
=(1+1/2+1/3+1/4) x(1/2+1/3+1/4+1/5-1/2-1/3-1/4)-1/5 x(1/2+1/3+1/4)
=(1+1/2+1/3+1/4) x1/5-1/5 x(1/2+1/3+1/4)
=1/5 x(1+1/2+1/3+1/4-1/2-1/3-1/4)
=1/5 x1
=1/5
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