Question

已知a,b,c为实数,且|a-2|+（√a+b-4 ）+(c+3)²=0 若ax+b=c,求x的值

过程也要滴~~~

Answer 1

|a-2|+（√a+b-4 ）+(c+3)²=0
a-2=0,
a+b-4=0
c+3=0
a=2, b=2, c=-3
ax+b=c
即2x+2=-3
2x=-5
x=-2.5

Answer 2

解：∵|a-2|+（√a+b-4 ）+(c+3)²=0
∴|a-2|=0, （√a+b-4 ）=0, (c+3)²=0
a-2=0, a+b-4=0, c+3=0
∴a=2, b=2, c=-3.
将a=2, b=2, c=-3.代入ax+b=c，得
2x+2=-3
2x=-5
x=-2.5