Question

怎么解这道题

Answer 1

=lim(x→2)[(x+2)(x-2)]/[(x+2)(x-3)]
=lim(x→2)(x-2)/(x-3)
=(2-2)/(2-3)
=0

追问

难道答案错了

追答

哦，我因式分解搞错了：x^2-5x+6=(x-2)(x-3)
=lim(x→2)[(x+2)(x-2)]/[(x-2)(x-3)]
=lim(x→2)(x+2)/(x-3)
=(2+2)/(2-3)
=-4

追问

喔喔，谢啦

我就是不懂因式分解

那这个第六小题呢