第二问求解
2个回答
展开全部
请闭派扮轿灶羡帆
本回答被提问者和网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
x^2+(y-1)^2=1 (1)
2x + 2(y-1).dy/dx = 0
dy/dx = -x/(y-1)
S=2x+y
dS/dx
=2 + dy/dx
=2 -x/(y-1)
dS/晌如dx =0
2 -x/(y-1) =0
2(y-1) -x =0
y= (x+2)/2 (2)
sub (2) into (1)
x^2+(y-1)^2=1
x^2+((x+2)/宴圆启2-1)^2=1
4x^2=4
x= 1 or -1
x=1, y=3/腔滑2 (max)
x=-1, y = 1/2 (min)
S=2x+y
max S = 2(1) + 3/2 = 7/2
min S = 2(-1) + 1/2 = - 3/2
2x + 2(y-1).dy/dx = 0
dy/dx = -x/(y-1)
S=2x+y
dS/dx
=2 + dy/dx
=2 -x/(y-1)
dS/晌如dx =0
2 -x/(y-1) =0
2(y-1) -x =0
y= (x+2)/2 (2)
sub (2) into (1)
x^2+(y-1)^2=1
x^2+((x+2)/宴圆启2-1)^2=1
4x^2=4
x= 1 or -1
x=1, y=3/腔滑2 (max)
x=-1, y = 1/2 (min)
S=2x+y
max S = 2(1) + 3/2 = 7/2
min S = 2(-1) + 1/2 = - 3/2
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
