Question

c语言菜鸡 ，求大佬一个代码，简单点，如图，谢谢

Answer 1

代码如下

void main() {

int a, b, c,d=0;

for (a = 0; a <= 4; a++) {

for (b = 0; b <= 10; b++) {

for (c = 0; c <= 20; c++)

if (5 * a + 2 * b + c==20) {

printf("有%d个1元+%d个2元+%d个5元\n", c, b, a);

d++;

}

}

}

printf("共%d种方案", d);

}

Answer 2

void main()
{
int t,a1,a2,a5;

for(a1=0;a1<20;a1++)

{
for(a2=0;a2<20;a2++)

{

for(a5=0;a5<20;a5++)

{
if(a1+a2*2+a5*5==20)printf("1$*%02d,2$*%02d,5$*%02d\r\n",a1,a2,a5);
}

}

}

}