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先化简,再求值:(x-2分之x-x+2分之x)除以x-2分之4x,其中x=-4
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[x/(x-2)-x/(x+2)]÷[4x/(x-2)]
=[x(x+2)-x(x-2)]/[(x-2)(x+2)]×[(x-2)/4x]
=4x/[(x-2)(x+2)]×[(x-2)/4x]
=1/(x+2)
=1/(-4+2)
=-1/2
=[x(x+2)-x(x-2)]/[(x-2)(x+2)]×[(x-2)/4x]
=4x/[(x-2)(x+2)]×[(x-2)/4x]
=1/(x+2)
=1/(-4+2)
=-1/2
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