数学题。。。。分式
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原始=( (a²-1)/(a-1)²+1/(a-1)² )*(a-1)/a
=a²/(a-1)²*(a-1)/a
=a/(a-1)
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=a²/(a-1)²*(a-1)/a
=a/(a-1)
微凉的生活,温暖的心!37度_微凉团队真诚为您解答!
满意请采纳!谢谢!
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原式=((a+1)/(a-1)+1/(a-1)^2)X(a-1)/a
=[(a+1)/(a-1)X(a-1)+1/(a-1)^2X(a-1)]/a
=[(a+1)+1/(a-1)]/a
=[((a+1)(a-1)+1)/(a-1)]/a
=[(a^2-1+1)/(a-1)]/a
=a^2/(a(a-1))
=a/(a-1)
=[(a+1)/(a-1)X(a-1)+1/(a-1)^2X(a-1)]/a
=[(a+1)+1/(a-1)]/a
=[((a+1)(a-1)+1)/(a-1)]/a
=[(a^2-1+1)/(a-1)]/a
=a^2/(a(a-1))
=a/(a-1)
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