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∫(2/5->3/5) (x-x^2) dx
=[(1/2)x^2 -(1/3)x^3](2/5->3/5)
=[ (1/2)(9/25) -(1/3)(27/125) ] - [ (1/2)(4/25) - (1/3)(8/125)]
=(1/2)( 9/25 -4/25) - (1/3)( 27/125-8/125)
=1/10 - 19/375
=(75-38)/750
=37/750
=[(1/2)x^2 -(1/3)x^3](2/5->3/5)
=[ (1/2)(9/25) -(1/3)(27/125) ] - [ (1/2)(4/25) - (1/3)(8/125)]
=(1/2)( 9/25 -4/25) - (1/3)( 27/125-8/125)
=1/10 - 19/375
=(75-38)/750
=37/750
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