m/(m+3)+6/(9-m²)+2/(m+3)=多少 求过程TAT 高手进来
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m/(m+3)+6/(9-m²)+2/(m+3)
=[(m+2)(m-3)/(m+3)(m-3)]+[6/(9-m²)]
=(m^2-m-6)/(m²-9)-6/(9-m²)
=(m^2-m-12)/(m²-9)
=(m-4)(m+3)//(m+3)(m-3)
=(m-4)/(m-3)
=[(m+2)(m-3)/(m+3)(m-3)]+[6/(9-m²)]
=(m^2-m-6)/(m²-9)-6/(9-m²)
=(m^2-m-12)/(m²-9)
=(m-4)(m+3)//(m+3)(m-3)
=(m-4)/(m-3)
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=m/(m+3)+1/(m+3)-1/(m-3)+2/(m+3)
=(m+1+2)/(m+3)-1/(m-3)
=1-1/(m-3)
=(m-4)/(m-3)
=(m+1+2)/(m+3)-1/(m-3)
=1-1/(m-3)
=(m-4)/(m-3)
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