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(3x+2)/(x²-x-2)+[1-1/(x+1)]÷[1+1/(x-1)]
=(3x+2)/(x-2)(x+1)+[(x+1-1)/(x+1)]÷[(x-1+1)/(x-1)]
=(3x+2)/(x-2)(x+1)+x/(x+1)*(x-1)/x
=(3x+2)/(x-2)(x+1)+(x-1)/(x+1)
=[3x+2+(x-1)(x-2)]/(x-2)(x+1)
=(x²+4)/(x-2)(x+1)
=(9+4)/(3-2)(3+1)
=13/4
=(3x+2)/(x-2)(x+1)+[(x+1-1)/(x+1)]÷[(x-1+1)/(x-1)]
=(3x+2)/(x-2)(x+1)+x/(x+1)*(x-1)/x
=(3x+2)/(x-2)(x+1)+(x-1)/(x+1)
=[3x+2+(x-1)(x-2)]/(x-2)(x+1)
=(x²+4)/(x-2)(x+1)
=(9+4)/(3-2)(3+1)
=13/4
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