Question

（x^4-2x^2y^2+y^4)/(x+y)^2/(x-y)

要有详细过程

Answer 1

原式=（x^2-y^2)^2/(x+y)^2/(x-y)=(x-y)^2/(x-y)=x-y,其中(x^2-y^2)^2=（x+y)^2(x-y)^2用平方差公式分解因式。

Answer 2

（x^4-2x^2y^2+y^4)/(x+y)^2/(x-y)=(x^2-y^2)2/(x+y)^2/(x-y)=(x+y)^2(x-y)^2/(x+y)^2/(x-y)=(x-y)