Question

先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1)，其中x=2倍根号3+1

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Answer 1

您好：

x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1)
=（x-4）/（x+1）（x-1）÷（x+1）（x-4）/(x+1)²+1/(x-1)
=1/(x-1)+1/(x-1)
=2/(x-1)
=2/(2√3+1-1)
=2/2√3
=1/√3
=√3/3

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Answer 2

（x-4）/(x-1)(x+1）乘以(x-1)²/()x+1(x-4))+1/(x-1)
=（x+1）/（x-1）+1/(x-1)
=()x+2(x-1)
=1+(根号3/2)