Question

(2n+1)²-(2n-1)²分解因式

Answer 1

原式=[(2n+1)+(2n-1)][(2n+1)-(2n-1)]
=(4n)*2
=8n

Answer 2

[(2n+1)+(2n-1)]*[(2n+1)-(2n-1)]=8n

Answer 3

解：原式＝﹙2n＋1－2n＋1﹚﹙2n＋1＋2n－1﹚
＝8n.