Question

因式分解 要过程

x^2-y^2+x-y
a^9-ab^2-a^2-ab
4x^2-a^2-6a-9
ab-a-b+1
m^3+4m^4-8-32m

Answer 1

x^2-y^2+x-y
=(x^2-y^2)+(x-y)
=(x-y)(x+y)+(x-y)
=(x-y)(x+y+1)

a^9-ab^2-a^2-ab
=a(a^8-b^2-a-b)

4x^2-a^2-6a-9
=4x^2-(a+3)^2
(2x+a+3)(2x-a-3)

ab-a-b+1
=(ab-a)-(b-1)
=a(b-1)-(b-1)
=(b-1)(a-1)

m^3+4m^4-8-32m
=m^3(1+4m)-8(1+4m)
=(m^3-8)(1+4m)
=(m-2)(m²+2m+4)(1+4m)

Answer 2

x^2-y^2+x-y=(x+y)(x-y)+(x-y)=(x-y)(x+y+1)
a^9-ab^2-a^2-ab=
4x^2-a^2-6a-9
ab-a-b+1
m^3+4m^4-8-32m

Answer 3

x^2-y^2+x-y
=(x²-y²)+(x-y)
=(x+y)(x-y)+(x-y)
=(x-y)(x+y+1)

a^3-ab^2-a^2-ab
=(a³-ab²)-(a²+ab)
=a(a²-b²)-a(a+b)
=a(a+b)(a-b)-a(a+b)
=a(a+b)(a-b-1)

4x^2-a^2-6a-9
=(2x)²-(a²+6a+9)
=(2x)²-(a+3)²
=(2x+a+3)(2x-a-3)

ab-a-b+1
=a(b-1)-(b-1)
=(b-1)(a-1)

m^3+4m^4 -8-32m
=m³(1+4m)-8(1+4m)
=(1+4m)(m³-8)
=(1+4m)(m-2)(m²+2m+4)

追问

谢谢 我还想问 ：5x^3-6x+1
a^5+a+1
(2x^2-3x+1)^2-22x^2+33x-11

追答

5x^3-6x+1
=5x³-5x-(x-1)
=5x(x+1)(x-1)-(x-1)
=(x-1)(5x²+5x-1)

a^5+a+1 这个搞错了

(2x^2-3x+1)^2-22x^2+33x-11
=(2x²-3x+1)²-11(2x²-3x+1)
=(2x²-3x+1)(2x²-3x+1-11)
=(2x²-3x+1)(2x²-3x-10)

追问

a^5+a+1 可题目上就是这样的 真的不行的话那就算了。

追答

不行，请采纳

追问

再问一个就采纳了 （x+1)(x+2)（x+3)(x+4)-24

追答

不行了，怎么可以这样无休止的追问，请采纳，谢谢
要想解决此题，请再求助