2个回答
展开全部
a²/(a-1)-(a+1)
=a²/(a-1)-(a+1)(a-1)/(a-1)
=[a²-(a-1)(a+1)]/(a-1)
=(a²-a²+1)/(a+1)(a-1)
=1/(a-1)(a+1)
[b/(a²-ab)+a/(b²-ab)]÷(a-b)/ab
=[b/a(a-b)+a/b(b-a)]÷(a-b)/ab
=[b²/ab(a-b)-a²/ab(a-b)]÷(a-b)/ab
=(b²-a²）/ab(a-b)*ab/(a-b)
=(a+b)(b-a)/ab(a-b)*ab/(a-b)
=-(a+b)/(a-b)
=a²/(a-1)-(a+1)(a-1)/(a-1)
=[a²-(a-1)(a+1)]/(a-1)
=(a²-a²+1)/(a+1)(a-1)
=1/(a-1)(a+1)
[b/(a²-ab)+a/(b²-ab)]÷(a-b)/ab
=[b/a(a-b)+a/b(b-a)]÷(a-b)/ab
=[b²/ab(a-b)-a²/ab(a-b)]÷(a-b)/ab
=(b²-a²）/ab(a-b)*ab/(a-b)
=(a+b)(b-a)/ab(a-b)*ab/(a-b)
=-(a+b)/(a-b)
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
a²/a-1-(a+1)
=a²/a-1 - (a+1)(a-1)/a-1
=a²-a²+1/a-1
=1/a-1
(b/a²-ab+a/b²-ab)÷a-b/ab
=[b/a(a-b) - a/b(a-b)]× ab/a-b
=b²-a²/ab(a-b) × ab/a-b
=(b-a)(b+a)/ab(a-b)× ab/a-b
=-(b+a)/ab× ab/a-b
=-(b+a)/a-b
=a²/a-1 - (a+1)(a-1)/a-1
=a²-a²+1/a-1
=1/a-1
(b/a²-ab+a/b²-ab)÷a-b/ab
=[b/a(a-b) - a/b(a-b)]× ab/a-b
=b²-a²/ab(a-b) × ab/a-b
=(b-a)(b+a)/ab(a-b)× ab/a-b
=-(b+a)/ab× ab/a-b
=-(b+a)/a-b
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
