(1+1/2)(1+1/2²)(1+二的4次方分之一)(1+2的8次方分之一)+二的十五次方分之一
1个回答
展开全部
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8) 这个式子*一个(1-1/2)然后除以一个(1-1/2),
原式=(1-1/2)/(1-1/2)*(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^4)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^8)(1+1/2^8)*2+1/2^15
=(1-1/2^16)*2+1/2^15
=2-1/2^15
原式=(1-1/2)/(1-1/2)*(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^4)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^8)(1+1/2^8)*2+1/2^15
=(1-1/2^16)*2+1/2^15
=2-1/2^15
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询