Question

使用循环编程，在屏幕上输出九九乘法表。

Answer 1

#include<stdio.h>
void main()
{
int i,j;
for(i=1;i<=9;i++)
{for(j=1;j<=i;j++)<br/> {printf("%d*%d=%d\t",j,i,j*i);}
printf("\n");
}
}

Answer 2

#include<stdio.h>
main()
{
int a,b,s;
for(a=1;a<10;a++)
{
for(b=1;b<10;b++)
{
s=a*b;
printf("%d*%d=%-3d",a,b,s);
}
printf("\n");
getch();
}
}

Answer 3

用Python吧，比C简单多了：
for i in range( 1, 10 ):
for j in range( 1, 10 ):
print '%d * %d = %d\t' % ( i, j, i*j ),
print

Answer 4

看 看 C# 吧

using System;
using System.Collections.Generic;
using System.Text;

namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
for (int i = 0; i <= 9; i++)
{
for (int j = 0; j <= i; j++)
{

Console.Write("{0}*{1}={2}",i,j,i*j+" ");
}

Console.WriteLine();
}

}
}
}