Question

数学题目计算1/(a-b)+2a/(a2+b2)+(4a3)/(a4+b4)+1/a+b

1/(a-b)+2a/(a2+b2)+(4a3)/(a4+b4)+1/a+b

Answer 1

1/（a-b) + 1/（a+b) + 2a / (a2+b2) + 4a3次/（a4次+b4次）
=[(a+b)+(a-b)]/（a2-b2) + 2a / (a2+b2) + 4a3次/（a4次+b4次）
=2a/（a2-b2) + 2a / (a2+b2) + 4a3次/（a4次+b4次）
=2a[(a2+b2)+(a2-b2)]/(a4-b4)+ 4a3次/（a4次+b4次）
= 4a3次/（a4次-b4次）+4a3次/（a4次+b4次）
= 8a7次/（a8次-b8次）希望对你有帮助 望采纳 谢谢你！

Answer 2

1/(a-b)+2a/(a2+b2)+(4a^3)/(a^4+b^4)+1/(a+b) = 1/(a-b)+1/(a+b) + 2a/(a2+b2)+(4a3)/(a^4+b^4) = [(a+b)+(a-b)]/[(a+b)*(a-b)] + 2a/(a�0�5+b�0�5)+(4a^3)/(a^4+b^4) =2a/(a�0�5-b�0�5)+2a/(a�0�5+b�0�5)+(4a^3)/(a^4+b^4) =2a[(a�0�5+b�0�5) + (a�0�5-b�0�5)]/[(a�0�5-b�0�5)(a�0�5+b�0�5)] +(4a^3)/(a^4+b^4) =4a^3/(a^4-b^4)+(4a^3)/(a^4+b^4) =4a^3 *[(a^4-b^4)+(a^4+b^4)]/[(a^4-b^4)(a^4+b^4)] =8a^7/(a^8-b^8)