Question

在C#中怎么样获取openFileDialog打开的名称不要路劲

Answer 1

string path = this.openfiledialog1.filename
然后对path 用\来split 取数组的最后一个就是文件名称了

Answer 2

                //using System.IO;
                string FileName = Path.GetFileName(fullName);
                string FileNameWithoutExtension = Path.GetFileNameWithoutExtension(fullName);

Answer 3

FileInfo fileInfo = new FileInfo(filePath);
String filename = filePath.Name;