2014-01-12
展开全部
3x�0�5+4xy-y�0�5
=3x�0�5+4xy+4y�0�5/3-2xy-4y�0�5/3-y�0�5
=1/3(9x�0�5+12xy+4y�0�5)-7y�0�5/3
=1/3[(3x+2y)�0�5-7y�0�5]
=1/3[3x+2y+(√7)y][3x+2y-(√7)y]
或者用参数法:令 3x2+4xy-y2 =3(x+ay)(x+by)=3x2+3(a+b)xy+3aby2
对应求解3a+3b=4.3ab=-1联立求解得出a.b ,
=3x�0�5+4xy+4y�0�5/3-2xy-4y�0�5/3-y�0�5
=1/3(9x�0�5+12xy+4y�0�5)-7y�0�5/3
=1/3[(3x+2y)�0�5-7y�0�5]
=1/3[3x+2y+(√7)y][3x+2y-(√7)y]
或者用参数法:令 3x2+4xy-y2 =3(x+ay)(x+by)=3x2+3(a+b)xy+3aby2
对应求解3a+3b=4.3ab=-1联立求解得出a.b ,
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询