Question

求y=[根号下2sin(2x+π/3)-1]定义域

Answer 1

要使函数有定义,必须且仅需
2sin(2x+π/3)-1≥0
∴ sin(2x+π/3)≥1/2
π/6+2kπ≤2x+π/3≤5π/6+2kπ
-π/12+kπ≤x≤π/4+kπ
即函数的定义域为{x|-π/12+kπ≤x≤π/4+kπ,k∈Z}