Question

编写程序通过调用随机函数给5*6的2维数组10-40的整数，求出二维数每行元素的平均值

帮帮忙啊 啊啊啊啊

Answer 1

#include "stdio.h"
#include "conio.h"
#include "time.h"

void main()
{
int i,j;
int a[5][6];
double b[5]={0};

srand(time(0));
for(i=0;i<5;i++)
{
for(j=0;j<6;j++)
{
a[i][j]=rand()%31 + 10;
b[i]+=a[i][j];
}
b[i]=b[i]/6;
}

/*输出就不写了,a为得到的二维数组,b为每行元素的平均值*/
}

Answer 2

#include <stdio.h>
void f(int a[5][6])
{int i,j,k;
int sum=0;
srand( (unsigned)time( NULL ) );
for(i=0;i<5;i++)
{
for(j=0;j<6;j++)
{k=rand()%31+10;
a[i][j]=k;
printf("%3d",a[i][j]);
}
printf("\n");
}
printf("mei yi hang ping jun zhi ru xia:\n");
for(i=0;i<5;i++)
{
for(sum=0,j=0;j<6;j++)
sum+=a[i][j];
sum=sum/6;
printf("di %d hang ping jun zhi:%d\n",i+1,sum);
}
}

main()
{int a[5][6];
f(a);
getch();
}

Answer 3

上面两个存在重复问题

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
srand(time(0));

int m[5][6];

for (int i = 0; i < 30; i++)
{
m[0][i] = i + 10;
}

for (int i = 0; i < 30; i++)
{
int j = rand() % 30;
int t = m[0][i];

m[0][i] = m[0][j];
m[0][j] = t;
}

for (int i = 0; i < 5; i++)
{
int x = 0;

for (int j = 0; j < 6; j++)
{
x += m[i][j];
}

printf("%f\n", (float)x / 6);
}

return 0;
}