Question

数据结构 L.elem=new ElemType[ListSize]

#include <stdio.h>
#include <stdlib.h>
#define ListSize 100
typedef int ElemType;
typedef struct
{
ElemType elem[ListSize];
int length;
}SeqList;

void InitList(SeqList& L){
L.elem=new ElemType[ListSize];
if (L.elem==NULL)
{
printf("储存分配失败!\n");
exit(1);
}
L.length=0;
}
报错：

error C2440: '=' : cannot convert from 'int *' to 'int [100]'
There are no conversions to array types, although there are conversions to references or pointers to arrays

Answer 1

#include <stdio.h>
#include <stdlib.h>
#define ListSize 100
typedef int ElemType;
typedef struct  
{
	ElemType *elem;//这里应该定义指针的
	int length;
}SeqList;

void InitList(SeqList& L){
	L.elem=new ElemType[ListSize];
	if (L.elem==NULL)
	{
		printf("储存分配失败!\n");
		exit(1);
	}
	L.length=0;
}
int main()
{
	SeqList L;
	InitList(L);
}