Question

C语言编程计算1-2+3-4+5-6+...+99-100

如题..要在win-tc下能运行！

Answer 1

main()
{
int i,sum=0;
for(i=1;i<101;i++)
sum+=(i%2)?i:-i;
printf("1-2+3-...+99-100=%d",sum);
getch();
}

Answer 2

#include <stdio.h>
int main()
{

int sum=0;
int i=1, j=2, k=3;
while(i<100)
{
sum+=i*j*k;
i+=2;
j+=2;
k+=2;
}
printf("The sum is:%d\n", sum);
}

Answer 3

main()
{
int i,result=0;
for(i=1;i<101;i++)
{
if(i%2==1)
result+=i;
else
result-=i;
}
printf("1-2+3-...+99-100=%d",result);
}

Answer 4

#include <stdio.h>

main()
{
int i,t,sum;
i=1;
sum=0;
for(t=1;t<=100;t++)
{
sum=sum+i*t;
i=-i;
}
printf("%d\n",sum);
}

Answer 5

#include "math.h"
main()
{ int i,n,sum=0;
for(i=1;i<=100;i++)
{n=-1;<br/>sum=n^(i+1)*i+sum;<br/>}
printf("%d",sum);
}