Question

java编写程序求一元二次方程的根

Answer 1

import java.math.*;
public class demo{
/*
*
定义构造函数,写入A,B,C的值.
*/
private int a,b,c;
private Vector vector;

public demo(int a,int b,int c){
this.a = a;
this.b = b;
this.c = c;
}
public Vector test(){

if(b*b<4*a*c){

System.out.println("无跟");

vector.add("空");
}
else if(b*b=4*a*c){

int i = (-b-cbrt(b^2-4*a*c))/2/a

System.out.println("只有一个根"+i);

vector.add(i);
}
else if(b*b>4*a*c){

double x1=(-b-cbrt(b^2-4*a*c))/2/a

double x2=(-b+cbrt(b^2-4*a*c))/2/a

vector.add(x1);

vector.add(x2);
}
}

}
应该就是这个样子,我印象中写的,没有调试,你按照这个思路去改改

Answer 2

void equetion(int a,int b,int c)
{
//a*x*x+b*x+c = 0;
int x1,x2;
x1= (-b+sqrt(b*b-4*a*c))/(2*a);
x2= (-b-sqrt(b*b-4*a*c))/(2*a);
}

Answer 3

不懂啊啊啊 啊