帮我计算一下这道题,谢谢!
2个回答
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(2)1/(x+1)-1/(x+2)-1/(x+3)+1/(x+4)
=[1/(x+1)+1/(x+4)]-[1/(x+2)+1/(x+3)]
=[(x+4)+(x+1)]/(x2+5x+4)-[(x+2)+(x+3)]/(x^2+5x+6)
=(2x+5)/(x^2+5x+4)-(2x+5)/(x^2+5x+6)
=(2x+5)[1/(x^2+5x+4)-1/(x^2+5x+6)]
=(2x+5)[(x^2+5x+6-x^2-5x-4)/(x^2+5x+4)(x^2+5x+6)]
=2(2x+5)/(x+1)(x+2)(x+3)(x+4)。
=[1/(x+1)+1/(x+4)]-[1/(x+2)+1/(x+3)]
=[(x+4)+(x+1)]/(x2+5x+4)-[(x+2)+(x+3)]/(x^2+5x+6)
=(2x+5)/(x^2+5x+4)-(2x+5)/(x^2+5x+6)
=(2x+5)[1/(x^2+5x+4)-1/(x^2+5x+6)]
=(2x+5)[(x^2+5x+6-x^2-5x-4)/(x^2+5x+4)(x^2+5x+6)]
=2(2x+5)/(x+1)(x+2)(x+3)(x+4)。
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