Question

求这个不定积分的过程

Answer 1

Answer 2

∫(2x^2+1)/[x^2.(x^2+1)] dx

=2∫ dx/(x^2+1) + ∫dx/[x^2.(x^2+1)]
=2arctanx + ∫[ 1/x^2-1/(x^2+1) ] dx
=2arctanx - 1/x - arctanx + C
=arctanx - 1/x + C