Question

（C语言编程题）统计所输入的字符串的长度和某个字符出现的次数。

Answer 1

假如输入字符串MYString 求出现'a'次数:
#include<stdio.h>
#include<string.h>
void main()
{
string MYString;
char MYChar='a';
int Count=0;
scanf("%s",MYString);
for(int i = 0 ; i < MYString.length ; i ++ )
{
if(MYString[i]==MYChar)
Count++;
}
printf("字符串长度为:%d 出现" & MYChar & "的次数为%d" ,MYString.length,Count);

}

Answer 2

#include<stdio.h>
main()
{
char str[80],c;
int sum1=0, sum2=0;
gets(str);
gets(a); //输入要统计的字符出现的次数//
while(str[sum1]!='\0')
{
if(str[sum1]==c)
sum2++;
sum1++;
}
printf("the string has %d character.",sum1);
printf("the charcater %c exist %d times.",c,sum2 );

}

Answer 3

#include"stdio.h"
#include"string.h"
main()
{int i,j,b[26];
char a[30];
for(i=0;i<26;i++)
b[i]=0;
gets(a);
printf("the length is %d\n",strlen(a));
for(i=0;i<strlen(a);i++)
{for(j=0;j<26;j++)
if(a[i]=65+j || a[i]=97+j)
b[j]+=1;}
for(i=0;i<26;i++)
printf("%c: %d ",65+i,b[i]);
}