∫y/(1-y)^2dy 怎么求啊
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∫[y/(1-y)²]dy
=∫[(y-1+1)/(y-1)²]dy
=∫[1/(y-1) +1/(y-1)²]dy
=∫[1/(y-1)]dy+∫[1/(y-1)²]d(y-1)
=ln|y-1| -(y-1)⁻¹+C
=∫[(y-1+1)/(y-1)²]dy
=∫[1/(y-1) +1/(y-1)²]dy
=∫[1/(y-1)]dy+∫[1/(y-1)²]d(y-1)
=ln|y-1| -(y-1)⁻¹+C
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