Question

有四位数,4,5,12,13,怎样运算使结果等于24?至少两种算法?

Answer 1

(5-(12-13))*4
((5-12)+13)*4
((5+13)-12)*4
(5+(13-12))*4
4-((5-12)-13)
(4-(5-12))+13
4-(5-(12+13))
((4-5)+12)+13
(4-5)+(12+13)
4*(5-(12-13))
4*((5-12)+13)
4-((5-13)-12)
(4-(5-13))+12
4-(5-(13+12))
((4-5)+13)+12
(4-5)+(13+12)
4*((5+13)-12)
4*(5+(13-12))
4+(12-(5-13))
(4+12)-(5-13)
((4+12)-5)+13
4+((12-5)+13)
(4+(12-5))+13
((4+12)+13)-5
4+((12+13)-5)
(4+(12+13))-5
4+(12+(13-5))
(4+12)+(13-5)
4+(13-(5-12))
(4+13)-(5-12)
((4+13)-5)+12
4+((13-5)+12)
(4+(13-5))+12
4*((13+5)-12)
4*(13+(5-12))
((4+13)+12)-5
4+((13+12)-5)
(4+(13+12))-5
4+(13+(12-5))
(4+13)+(12-5)
4*(13-(12-5))
4*((13-12)+5)
12-((5-4)-13)
(12-(5-4))+13
12-(5-(4+13))
((12-5)+4)+13
(12-5)+(4+13)
12-((5-13)-4)
(12-(5-13))+4
12-(5-(13+4))
((12-5)+13)+4
(12-5)+(13+4)
12+(4-(5-13))
(12+4)-(5-13)
((12+4)-5)+13
12+((4-5)+13)
(12+(4-5))+13
((12+4)+13)-5
12+((4+13)-5)
(12+(4+13))-5
12+(4+(13-5))
(12+4)+(13-5)
12/(4/(13-5))
(12/4)*(13-5)
12+(13-(5-4))
(12+13)-(5-4)
((12+13)-5)+4
12+((13-5)+4)
(12+(13-5))+4
12*((13-5)/4)
(12*(13-5))/4
((12+13)+4)-5
12+((13+4)-5)
(12+(13+4))-5
12+(13+(4-5))
(12+13)+(4-5)
13-((5-4)-12)
(13-(5-4))+12
13-(5-(4+12))
((13-5)+4)+12
(13-5)+(4+12)
(13-5)/(4/12)
((13-5)/4)*12
13-((5-12)-4)
(13-(5-12))+4
13-(5-(12+4))
((13-5)+12)+4
(13-5)+(12+4)
((13-5)*12)/4
(13-5)*(12/4)
((13+5)-12)*4
(13+(5-12))*4
13+(4-(5-12))
(13+4)-(5-12)
((13+4)-5)+12
13+((4-5)+12)
(13+(4-5))+12
((13+4)+12)-5
13+((4+12)-5)
(13+(4+12))-5
13+(4+(12-5))
(13+4)+(12-5)
(13-(12-5))*4
((13-12)+5)*4
13+(12-(5-4))
(13+12)-(5-4)
((13+12)-5)+4
13+((12-5)+4)
(13+(12-5))+4
((13+12)+4)-5
13+((12+4)-5)
(13+(12+4))-5
13+(12+(4-5))
(13+12)+(4-5)
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