Question

16（a-b）²-9（a+b）²分解因式

Answer 1

16（a-b）²-9（a+b）²
=[4（a-b）]²-[3（a+b）]²
=[4（a-b）+3（a+b）][4（a-b）-3（a+b）]
=(4a-4b+3a+3b)(4a-4b-3a-3b)
=(7a-b)(a-7b)

追问

还有简单的吗