
高等数学 求第二题详细解释
1个回答
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(2) 由对称性得
I = ∯<∑> y^2dS = ∯<∑> z^2dS = ∯<∑> x^2dS
3I = ∯<∑> (x^2+y^2+z^2)dS = R^2 ∯<∑>dS
= R^2 * 4πR^2 = 4πR^4, I = (4/3)πR^4
I = ∯<∑> y^2dS = ∯<∑> z^2dS = ∯<∑> x^2dS
3I = ∯<∑> (x^2+y^2+z^2)dS = R^2 ∯<∑>dS
= R^2 * 4πR^2 = 4πR^4, I = (4/3)πR^4
追问
能具体说一下对称性吗
追答
∑ 是半径为 R 的球面, 该球面对 x, y, z 轴都对称。
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