Question

c语言菜单编写

#include <stdio.h>#include <stdlib.h>#include <time.h>void menu(){ printf("\t\t [1]Stage 1\n"); printf("\t\t [2]Stage 2\n"); printf("\t\t [3]Stage 3\n"); printf("\t\t [4]Stage 4\n"); printf("\t\t [5]Stage 5\n"); printf("\t\t [6]Stage 6\n"); printf("\t\t [7]Stage 7\n"); printf("\t\t [8]Stage 8\n"); printf("\t\t [9]Stage 9\n"); printf("\t\t [10]Stage 10\n"); printf("\t\t [11]Exit\n\n");}void keyDown(){ int choice; scanf("%d", &choice); switch (choice) { case 0: printf("退出程序\n"); exit(0); case 1: break; case 2: break; case 3: break; case 4: break; case 5: break; case 6: break; case 7: break; case 8: break; case 9: break; case 10: break; default: printf("输入错误\n"); } system("pause");}int main(){ while (1) { menu(); keyDown(); system("cls"); } return 0;}我想搞这种菜单 但是编完了有问题 麻烦大神告诉一下怎么改

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Answer 1

我按你的修改了一下，您看一下符合要求不？

下面是修改后的代码：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>

void menu()
{	
	printf("******* Menu Title *********\n");
	printf(" [1] Stage 1\n");	
	printf(" [2] Stage 2\n");	
	printf(" [3] Stage 3\n");	
	printf(" [4] Stage 4\n");	
	printf(" [5] Stage 5\n");	
	printf(" [6] Stage 6\n");	
	printf(" [7] Stage 7\n");	
	printf(" [8] Stage 8\n");	
	printf(" [9] Exit\n\n");

	printf(" >>");
}


void dosomething(void)
{
	
}

void keyDown()
{	
	int choice;	
	scanf("%d", &choice);	
	switch (choice)	
	{		
		case 1:	dosomething();break;	
		case 2:	dosomething();break;	
		case 3:	dosomething();break;	
		case 4:	dosomething();break;	
		case 5:	dosomething();break;	
		case 6:	dosomething();break;	
		case 7:	dosomething();break;	
		case 8:	dosomething();break;	
		case 9:	
			printf("退出程序\n");	
			exit(0);
		default:	printf("输入错误\n");	
	}	

	// 这句为了调试的
	printf("您输入的选项为：%d\n按任意键刷新", choice);
}


int main()
{	
	while (1)	
	{	
		menu();	
		keyDown();
		
		getch();
		system("cls");	
	}	
	return 0;
}

Answer 2

有问题？你想干什么呢