Question

把$.getJSON获得的数据放到js数组里怎么他的length是1呢

var a = new Array(new Array());
var c = new Array();
$.getJSON(
"/Mobile_Server/admin/rgraph.do?oper_type=1",
function(data) {
$.each(data.result, function(k, v) {
c.push(v.cm_name);
var d = new Array();
d.push(v.p0);
d.push(v.p25);
a.push(d);
d = null;
});
alert(a.length);//返回1
alert(a.length);//返回10
});
"/Mobile_Server/admin/rgraph.do?oper_type=1" 这个返回的数据是{"result":
[{"p25":"1","p0":"2","oper_type":"1"},
{"p25":"1","p0":"2","oper_type":"1"},
{"p25":"0","p0":"1","oper_type":"1"},
{"p25":"0","p0":"0","oper_type":"1"},
{"p25":"1","p0":"0","oper_type":"1",},
{"p25":"1","p0":"1","oper_type":"1"},
{"p25":"0","p0":"0","oper_type":"1"},
{"p25":"0","p0":"1","oper_type":"1"},
{"p25":"0","p0":"0","oper_type":"1"}]}
我想把a，c用在下面的代码里
var bar = new RGraph.Bar('myCanvas', a); //创建Bar对象
//alert(a);
bar.Set('chart.labels',c); //设置标签
//bar.Set('hmargin', 15);
bar.Set('linewidth', 115);
bar.Set('numyticks',1);
bar.Set('chart.gutter.left', 145); //距离左边位置
bar.Set('chart.background.grid', true); //是否显示网格
bar.Set('chart.title','客户级别'); //标题
bar.Set('chart.shadow', true); //阴影
bar.Draw();

Answer 1

var a = [
    []
];
var c = [];
$.getJSON("/Mobile_Server/admin/rgraph.do?oper_type=1", function (data) {
    /*返回结果
    {
      "result": [
        {"p25": "1", "p0": "2", "oper_type": "1"},
        {"p25": "1", "p0": "2", "oper_type": "1"},
        {"p25": "0", "p0": "1", "oper_type": "1"},
        {"p25": "0", "p0": "0", "oper_type": "1"},
        {"p25": "1", "p0": "0", "oper_type": "1", },
        {"p25": "1", "p0": "1", "oper_type": "1"},
        {"p25": "0", "p0": "0", "oper_type": "1"},
        {"p25": "0", "p0": "1", "oper_type": "1"},
        {"p25": "0", "p0": "0", "oper_type": "1"}
      ]
    }
    */
    $.each(data.result, function (k, item) {
        c.push(item.cm_name);//貌似没有这个属性
        a.push([item.p0 , item.p25]);
    });
    alert(a.length);//返回10
});

追问

a在$.getJSON里是有值，但是在外面没有值啊。我是想把通过$.getJSON获取的a值，c值用到下面的代码中去 var bar = new RGraph.Bar('myCanvas', a); //创建Bar对象
bar.Set('chart.labels',c); //设置标签
bar.Draw();

追答

哦，这样啊，肯定没值啊，你那个getJSON方法是异步执行的，所以没值

你需要做一些处理

var a = [
    []
];
var c = [];
$.getJSON("/Mobile_Server/admin/rgraph.do?oper_type=1", function (data) {
    $.each(data.result, function (k, item) {
        c.push(item.cm_name);//貌似没有这个属性
        a.push([item.p0 , item.p25]);
    });
}).done(function(){
  //这里使用a和c
  var bar = new RGraph.Bar('myCanvas', a);   //创建Bar对象  
        //alert(a);
        bar.Set('chart.labels',c); //设置标签  
        //bar.Set('hmargin', 15);
        bar.Set('linewidth', 115);
        bar.Set('numyticks',1);
        bar.Set('chart.gutter.left', 145);   //距离左边位置  
        bar.Set('chart.background.grid', true);  //是否显示网格  
        bar.Set('chart.title','客户级别');   //标题  
        bar.Set('chart.shadow', true); //阴影  
        bar.Draw();
});