(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
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(-1/3xy)^2*[xy(2x-y)-2x(xy-y^2)]
= (-1/3xy)^2*[xy(2x-y)-2xy(x-y)]
= (-1/3xy)^2*xy(2x-y-2x+2y)
= (1/9x^2y^2)*xy^2
=1/9x
= (-1/3xy)^2*[xy(2x-y)-2xy(x-y)]
= (-1/3xy)^2*xy(2x-y-2x+2y)
= (1/9x^2y^2)*xy^2
=1/9x
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