
第六题怎么写?
1个回答
展开全部
选D
查表得到HF的Ka
F- + H2O == HF + OH-,K=Kw/Ka
c-x……………x……x
c=0.1mol/L,[HF]=[OH-]=x,则[F-]=c-x
K = Kw/Ka = x^2/(c-x)
可解得x
pH = 14 - pOH = 14 + log[OH-] = 14 + log x
查表得到HF的Ka
F- + H2O == HF + OH-,K=Kw/Ka
c-x……………x……x
c=0.1mol/L,[HF]=[OH-]=x,则[F-]=c-x
K = Kw/Ka = x^2/(c-x)
可解得x
pH = 14 - pOH = 14 + log[OH-] = 14 + log x
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询