Question

1.(y+1)(y-1)=1-y 2.y²+y+1/4=0这俩方程都要因式分解怎么做啊~

急~

Answer 1

1. (y+1)(y-1)=1-y

   (y+1)(y-1)-(1-y)=0

   (y+1)(y-1)+(y-1)=0

   (y-1)(y+1+1)=0

   (y-1)(y+2)=0

   由y-1=0和y+2=0分别得出y=1和y=-2

2. y²+y+1/4=0

   (y+1/2)²=0

   由y+1/2=0得出y=-1/2