Question

求函数y=x＋1分之x的值域?

Answer 1

解由y=x/(x+1)
=(x+1-1）/(x+1)
=1-1/(x+1)
由1/(x+1)≠0
即-1/(x+1)≠0
即1-1/(x+1)≠1
即y≠1
故函数的值域为{y/y≠1}