Question

解方程(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=0

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Answer 1

方程两边同时乘x²-1:
(3x²+9x+7)(x-1)-(2x²+4x-3)(x+1)-(x³+x+1)=0
3x^3+9x^2+7x-3x^2-9x-7-(2x^3+4x^2-3X+2x^2+4x-3)-x^3-x-1=0
3x^3+6x^2-2x-7-2x^3-4x^2+3x-2x^2-4x+3-x^3-x-1=0
0*x^3+0*x^2-4x-7-1+3=0
-4x-5=0
-4x=5x
x=-5/4
经检验x=-5/4原方程解
望采纳谢谢