-2=log以a为底二的对数加log以a为底二的对数,求a
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-2=log以a为底二的对数加log以a为底二的对数,求a是-2
咨询记录 · 回答于2023-01-09
-2=log以a为底二的对数加log以a为底二的对数,求a
-2=log以a为底二的对数加log以a为底二的对数,求a是-2
(1)因为logaX+logaY=loga(XY),所卖锋消以loga(2)+loga(1/2)=loga(2*1/2)=loga(1)=0(2)logaX-logaY=loga(X/Y),所中知以基迹答案为-2
log(a)2+log(a)1/2 =log(a)2+log(a)2^[-1] =log(a)2-log(a)2 =0