Question

|a+b+2|=(2ab-1)⁴求(a+b)²/3ab-3ab/a+b-1

Answer 1

问：|a+b+2|=(2ab-1)⁴求(a+b)²/3ab-3ab/a+b-1

答：您好。由“a+b+2的决对值与(2ab-1)^4互为相反数”得a+b+2=0a+b=-22ab-1=0ab=1/2代入(a+b)^2/3ab-3ab/a+b+1得(a+b)^2/3ab-3ab/a+b+1=（-2）^2/(3*1/2)-(3*1/2)/(-2+1)=4/(3/2)-(3/2)/(-1)=8/3+3/2=25/6=4又6分之1希望我的回答能够对你有所帮助