求不定积分∫(5x³-3x²+2x-4)/x³dx
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=∫3x^4dx-∫5x^3dx-∫3xdx+∫4dx
=3/5x^5-5/4x^4-3/2x^2+4x+c
咨询记录 · 回答于2021-11-29
求不定积分∫(5x³-3x²+2x-4)/x³dx
=∫(x³判搜+2x-3x-2x+3)/(x²+2x-3)dx =∫x+3/(x²拍哗+2x-3)dx =∫xdx+3∫1/(x²+2x-3)dx =x²/2+3∫掘贺历1/[(x-1)(x+1)]dx =x²/2+3/4∫1/(x-1)-1/(x+3)]dx = x²/2+3/4ln|x-1|-3/4ln|x+3|+C
不对啊
你看看我给的题
你看看我给的题
=∫3x^4dx-∫5x^3dx-∫3xdx+∫4dx
=3/5x^5-5/4x^4-3/2x^2+4x+c