Question

设f(x)=2x−1，求f(0)，f(2) ，f(−5)

Answer 1

问：设f(x)=2x−1，求f(0)，f(2) ，f(−5)

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答：f（0）=-1

答：f（0）=-1f（2）=3f（-5）=-11

答：设f(x)=2x−1，求f(0)，f(2) ，f(−5)解题因为f(x)=2x−1所以f（0）=2×0-1=-1f（2）=2×2-1=3f（-5）=2×（-5）-1=-11所以f（0）=-1f（2）=3f（-5）=-11

答：设f(x)=2x−1，求f(0)，f(2) ，f(−5)解题因为f(x)=2x−1所以f（0）=2×0-1=-1f（2）=2×2-1=3f（-5）=2×（-5）-1=-11所以f（0）=-1f（2）=3f（-5）=-11

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问：那第三题和第四题选什么

答：需要升级一下服务

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