Question

已知y=根号y-x+3-根号x-y-3+2,化简根号x分之2y

Answer 1

问：已知y=根号y-x+3-根号x-y-3+2,化简根号x分之2y

答：：y=√(x-3)+√(3-x)+2 有意义则必须满足：x-3>=0 3-x>=0 解得：x=3 代入原式得：y=0+0+2=2 2x√(3y)=2*3*√(3*2)=6√6

答：x=(√3+√2)/(√3-√2)=(√3+√2)^2/(3-2)=(√3+√2)^2同理 y＝（√3-√2）^2xy=(√3+√2)^2(√3-√2)^2=(3-2)^2=1x-y=(√3+√2)^2-(√3-√2)^2=4√3x√2=4√6x+y=(√3+√2)^2+(√3-√2)^2=2x3+2x2=10(x^3-xy^2)/(x^4y+2x^3y^2+x^2y^3)=(x^2-y^2)/(x^3y+2x^2y^2+xy^3)=(x^2-y^2)/xy(x^2+2xy+y^2)=(x+y)(x-y)/xy(x+y）^2=(x-y)/xy(x+y)=(x-y)/(x+y)=4√6/10=2/5√6