Question

VB中如何随机产生两个100位以上的数据并实现竖式加减

Answer 1

问：VB中如何随机产生两个100位以上的数据并实现竖式加减

答：以下是产生两个100位以上的随机数并实现竖式加减的VB代码：```' 产生两个100位以上随机数Dim rand As New Random()Dim num1 As String = ""Dim num2 As String = ""For i As Integer = 1 To 100 num1 &= rand.Next(10) num2 &= rand.Next(10)Next' 实现竖式加法Dim sum As String = ""Dim carry As Integer = 0For i As Integer = 99 To 0 Step -1 Dim digitSum As Integer = CInt(num1(i)) + CInt(num2(i)) + carry sum = (digitSum Mod 10).ToString() & sum carry = digitSum \ 10Next

答：' 输出结果Console.WriteLine(num1)Console.WriteLine(num2)Console.WriteLine(sum)' 实现竖式减法Dim diff As String = ""Dim borrow As Integer = 0For i As Integer = 99 To 0 Step -1 Dim digitDiff As Integer = CInt(num1(i)) - CInt(num2(i)) - borrow If digitDiff < 0 Then digitDiff += 10 borrow = 1 Else borrow = 0 End If diff = digitDiff.ToString() & diffNext' 输出结果Console.WriteLine(num1)Console.WriteLine(num2)Console.WriteLine(diff)```

答：在以上代码中，首先使用随机数生成器产生了两个100位的随机数，然后分别实现了竖式加法和竖式减法，并输出了结果。在竖式加减的实现中，都采用了逐位相加/减的方法，从最后一位开始，一直到最高位为止。同时，需要注意进位和借位的情况。

问：这个结果显示错误哎，没有完整的代码吗

答：我去试试

答：以下是一个随机产生两个100位以上数据并实现竖式加减的VB代码：```vbDim num1, num2 As String' 随机产生100位以上数据For i = 1 To 100 num1 = num1 & Int(Rnd() * 10) num2 = num2 & Int(Rnd() * 10)Next' 竖式加法Dim carry As Integer = 0Dim sum As String = ""For i = num1.Length To 1 Step -1 Dim n1 As Integer = Val(num1(i)) Dim n2 As Integer = Val(num2(i)) Dim s As Integer = n1 + n2 + carry sum = (s Mod 10).ToString & sum carry = s \ 10NextIf carry > 0 Then sum = carry.ToString & sumEnd If

答：' 竖式减法Dim borrow As Integer = 0Dim diff As String = ""For i = num1.Length To 1 Step -1 Dim n1 As Integer = Val(num1(i)) Dim n2 As Integer = Val(num2(i)) Dim d As Integer = n1 - n2 - borrow If d 0 Then d = d + 10 borrow = 1 Else borrow = 0 End If diff = d.ToString & diffNextIf borrow > 0 Then diff = "Error"End IfConsole.WriteLine("加法结果为：" & sum)Console.WriteLine("减法结果为：" & diff)```

答：这段代码首先使用了VB中的Int函数和Rnd函数来随机产生一个100位的数字字符串。接着使用竖式加法和竖式减法的方法来计算结果，并将结果打印出来。需要注意的是，减法结果可能会产生“Error”，表示减法不可行，因为被减数小于减数。

答：您再试试这个

问：Option Base 1Dim a() As Integer, b() As Integer, m As Integer, n As IntegerPrivateSubCommand1_Click()Dim i As IntegerRandomizem = Int(Rnd * 201 + 100) Picture1.Print "随机生成第一个数为"ReDim a(m) As IntegerFor i = LBound(a) To UBound(a) If i = LBound(a) Then a(i) = Int(Rnd * 100) Mod 9 + 1 Else a(i) = Int(Rnd * 100) Mod 10 End IfNext iFor i = LBound(a) To UBound(a) Picture2.Print CStr(a(i));Next iPicture2.PrintEnd SubPrivate Sub Command2_接着上述代码继续写，并且是运行结果如上图所示，剩下的代码是

答：_Click()Dim i As Integer, j As IntegerRandomizen = Int(Rnd * m + 1)Picture1.Print "随机生成第二个数为第" & n & "位"ReDim b(n) As IntegerFor i = LBound(b) To UBound(b) b(i) = a(i + m - n) Next iFor i = UBound(a) To m - n + 1 Step -1 a(i) = a(i - n) Next iFor i = LBound(b) To UBound(b) Picture3.Print CStr(b(i));Next iPicture3.PrintFor i = LBound(a) To UBound(a) Picture4.Print CStr(a(i));Next iPicture4.PrintEnd Sub

答：试试这个吧

答：需要解释的话，我再写

问：那接下来的以竖式形式表示的加减法的代码呢

答：以下是将两个以竖式形式表示的整数进行加减运算的代码：Option Base 1Private Sub Command1_Click() Dim a() As Integer, b() As Integer, c() As Integer ' 定义数组变量 Dim i As Integer, j As Integer, k As Integer Dim m As Integer, n As Integer, p As Integer Dim s As String ' 输入两个整数，以字符串形式存储 s = InputBox("请输入被加数：") m = Len(s) ReDim a(m) As Integer For i = LBound(a) To UBound(a) a(i) = CInt(Mid(s, i, 1)) Next i s = InputBox("请输入加数：") n = Len(s) ReDim b(n) As Intege

答：For i = LBound(b) To UBound(b) b(i) = CInt(Mid(s, i, 1)) Next i

答：' 进行加法运算 p = IIf(m > n, m, n) ReDim c(p + 1) As Integer For i = LBound(c) To UBound(c) c(i) = 0 Next i k = p + 1 For i = m To 1 Step -1 c(k) = c(k) + a(i) k = k - 1 Next i k = p + 1 For i = n To 1 Step -1 c(k) = c(k) + b(i) k = k - 1 Next i For i = p + 1 To 2 Step -1 If c(i) > 9 Then c(i - 1) = c(i - 1) + 1 c(i) = c(i) Mod 10 End If Next i ' 输出加法

答：运算的结果 s = "" For i = IIf(c(1) > 0, 1, 2) To UBound(c) s = s & CStr(c(i)) Next i Picture1.Print s End SubPrivate Sub Command2_Click() Dim a() As Integer, b() As Integer, c() As Integer ' 定义数组变量 Dim i As Integer, j As Integer, k As Integer Dim m As Integer, n As Integer, p As Integer Dim s As String

答：' 输入两个整数，以字符串形式存储 s = InputBox("请输入被减数：") m = Len(s) ReDim a(m) As Integer For i = LBound(a) To UBound(a) a(i) = CInt(Mid(s, i, 1)) Next i s = InputBox("请输入减数：") n = Len(s) ReDim b(n) As Integer For i = LBound(b) To UBound(b) b(i) = CInt(Mid(s, i, 1)) Next i

答：进行减法运算 p = IIf(m > n, m, n) ReDim c(p) As Integer For i = LBound(c) To UBound(c) c(i) = 0 Next i k = p For i = m To 1 Step -1 c(k) = a(i) k = k - 1 Next i For i = n To 1 Step -1 c(k) = c(k) - b(i) k = k - 1 Next i

答：For i = n To 1 Step -1 c(k) = c(k) - b(i) k = k - 1 Next i For i = p To 2 Step -1 If c(i) 0 Then c(i - 1) = c(i - 1) - 1 c(i) = c(i) + 10 End If Next i ' 输出减法运算的结果 s = "" For i = IIf(c(1) > 0, 1, 2) To UBound(c) s = s & CStr(c(i)) Next i Picture1.Print s End Sub

答：以上~