Question

4.求下列函数的定义域:-|||-(1) y=2x/(x^2-2x+2)-|||-(2) y=(lg(3-x))/(1x+1)

Answer 1

问：4.求下列函数的定义域:-|||-(1) y=2x/(x^2-2x+2)-|||-(2) y=(lg(3-x))/(1x+1)

问：第四个

问：四题的4小题

答：第4题吗？

问：快了妈

答：4.求下列函数的定义域:-|||-(1) y=2x/(x^2-2x+2)x^2-2x+2=(x-1)^2+1定义域x∈R(2) y=(lg(3-x))/√丨x|-1)3-x>0且丨x丨-1>0x1或x<-1定义域为{x丨1

答：(3) y=1-x^2≥0且丨x丨<1-1≤ⅹ≤1且-1

答：(4) y=√lg{(5x-x^2)/4}lg{(5x-x^2)/4}≥05x-x^2﹥0且(5x-x^2)/4≥1即5x-x^2≥4x^2-5x+4≤0(x-4)(x-1)≤01≤x≤4定义域为{x丨1≤x≤4}

答：总之正确答案是(4) y=√lg{(5x-x^2)/4}(5x-x^2)/4>0解得5x-x^2>0x^2-5x<00