Question

设y=2πx-√x3,求y/

Answer 1

问：设y=2πx-√x3,求y/

答：亲，是求导数

答：你拍照，把题目补全

答：解法：利用变量代换，令u=2πx-√x3，则y=u。对u求导数，有：du/dx=2π-3/2x1/2由链式法则可得：dy/dx=du/dx*du/dy= (2π-3/2x1/2) *1 即：dy/dx=2π-3/2x1/2