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用两种方法求积分∫x²(x³-2)dx
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咨询记录 · 回答于2022-09-16
用两种方法求积分∫x²(x³-2)dx
用两种方法求积分∫x²(x³-2)dx是∫(x-2)²dx=1/3 (x-2)³+C的。用两种方法求积分∫x²(x³-2)dx的具体做法如下,∫(x-2)²dx=1/3 (x-2)³+C,∫ x/(x²-x-2) dx=1/2∫[(2x-1)+1]/x²-x-2dx=1/2∫d(x²-x-2)/(x²-x-2)+1/2∫1/(x²-x-2)dx=1/2ln(x²-x-2)+1/2∫ d(x-1/2)/[(x-1/2)²-(3/2)²]=1/2ln(x²-x-2)+1/2×1/3ln丨(x-2)/(x-1)丨+C=2/3ln丨x-2丨+1/3ln丨x+1丨+C
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