Question

18.(1)求值: log2(log216)+lg1/2-lg5

Answer 1

问：18.(1)求值: log2(log216)+lg1/2-lg5

答：log2(log216)+lg1/2-lg5＝log2(4)+lg1/2/5=2+lg1/10=2-1=1

答：扩展基本性质：　　1、a^(log(a)(b))=b　　2、log(a)(a^b)=b　　3、log(a)(MN)=log(a)(M)+log(a)(N);　　4、log(a)(M÷N)=log(a)(M)-log(a)(N);　　5、log(a)(M^n)=nlog(a)(M)　　6、log(a^n)M=1/nlog(a)(M)